b^2+2bc-80c^2=0

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Solution for b^2+2bc-80c^2=0 equation:


Simplifying
b2 + 2bc + -80c2 = 0

Reorder the terms:
2bc + b2 + -80c2 = 0

Solving
2bc + b2 + -80c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + -8c)(b + 10c) = 0

Subproblem 1

Set the factor '(b + -8c)' equal to zero and attempt to solve: Simplifying b + -8c = 0 Solving b + -8c = 0 Move all terms containing b to the left, all other terms to the right. Add '8c' to each side of the equation. b + -8c + 8c = 0 + 8c Combine like terms: -8c + 8c = 0 b + 0 = 0 + 8c b = 0 + 8c Remove the zero: b = 8c Simplifying b = 8c

Subproblem 2

Set the factor '(b + 10c)' equal to zero and attempt to solve: Simplifying b + 10c = 0 Solving b + 10c = 0 Move all terms containing b to the left, all other terms to the right. Add '-10c' to each side of the equation. b + 10c + -10c = 0 + -10c Combine like terms: 10c + -10c = 0 b + 0 = 0 + -10c b = 0 + -10c Remove the zero: b = -10c Simplifying b = -10c

Solution

b = {8c, -10c}

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